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12303112300022 = 26151556150011
BaseRepresentation
bin1011001100001000101010…
…1000110110010111110110
31121120011111001100100112202
42303002022220312113312
53103033233222100042
642055545522344502
72406604410032015
oct263021250662766
947504431310482
1012303112300022
113a137a2174185
1214685134bb132
136b3242261c2b
1430768c1daa7c
15165073957632
hexb308aa365f6

12303112300022 has 4 divisors (see below), whose sum is σ = 18454668450036. Its totient is φ = 6151556150010.

The previous prime is 12303112300019. The next prime is 12303112300133. The reversal of 12303112300022 is 22000321130321.

12303112300022 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 12303112299967 and 12303112300003.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3075778075004 + ... + 3075778075007.

It is an arithmetic number, because the mean of its divisors is an integer number (4613667112509).

Almost surely, 212303112300022 is an apocalyptic number.

12303112300022 is a deficient number, since it is larger than the sum of its proper divisors (6151556150014).

12303112300022 is an equidigital number, since it uses as much as digits as its factorization.

12303112300022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6151556150013.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 12303112300022 its reverse (22000321130321), we get a palindrome (34303433430343).

The spelling of 12303112300022 in words is "twelve trillion, three hundred three billion, one hundred twelve million, three hundred thousand, twenty-two".

Divisors: 1 2 6151556150011 12303112300022