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123031134345023 is a prime number
BaseRepresentation
bin11011111110010101101011…
…000011110001011100111111
3121010121122212021210220121022
4123332111223003301130333
5112111220230343020043
61113355420045254355
734625464126046402
oct3376255303613477
9533548767726538
10123031134345023
1136224235a17143
1211970311b643bb
135385a2b339228
142254a4accdd39
15e354c7390868
hex6fe56b0f173f

123031134345023 has 2 divisors, whose sum is σ = 123031134345024. Its totient is φ = 123031134345022.

The previous prime is 123031134345001. The next prime is 123031134345139. The reversal of 123031134345023 is 320543431130321.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 123031134345023 - 214 = 123031134328639 is a prime.

It is a super-2 number, since 2×1230311343450232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123031134545023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61515567172511 + 61515567172512.

It is an arithmetic number, because the mean of its divisors is an integer number (61515567172512).

Almost surely, 2123031134345023 is an apocalyptic number.

123031134345023 is a deficient number, since it is larger than the sum of its proper divisors (1).

123031134345023 is an equidigital number, since it uses as much as digits as its factorization.

123031134345023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 123031134345023 its reverse (320543431130321), we get a palindrome (443574565475344).

The spelling of 123031134345023 in words is "one hundred twenty-three trillion, thirty-one billion, one hundred thirty-four million, three hundred forty-five thousand, twenty-three".