Base | Representation |
---|---|
bin | 1011001100001000101111… |
… | …0111110100010110011111 |
3 | 1121120011112111022002010001 |
4 | 2303002023313310112133 |
5 | 3103033304022013434 |
6 | 42055551542155131 |
7 | 2406605051011042 |
oct | 263021367642637 |
9 | 47504474262101 |
10 | 12303133001119 |
11 | 3a13802923224 |
12 | 146851a422aa7 |
13 | 6b324662c4bc |
14 | 307690c68c59 |
15 | 165075696114 |
hex | b308bdf459f |
12303133001119 has 2 divisors, whose sum is σ = 12303133001120. Its totient is φ = 12303133001118.
The previous prime is 12303133001063. The next prime is 12303133001141. The reversal of 12303133001119 is 91110033130321.
It is a strong prime.
It is an emirp because it is prime and its reverse (91110033130321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12303133001119 - 217 = 12303132870047 is a prime.
It is a super-2 number, since 2×123031330011192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12303133001149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151566500559 + 6151566500560.
It is an arithmetic number, because the mean of its divisors is an integer number (6151566500560).
Almost surely, 212303133001119 is an apocalyptic number.
12303133001119 is a deficient number, since it is larger than the sum of its proper divisors (1).
12303133001119 is an equidigital number, since it uses as much as digits as its factorization.
12303133001119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 28.
The spelling of 12303133001119 in words is "twelve trillion, three hundred three billion, one hundred thirty-three million, one thousand, one hundred nineteen".
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