Base | Representation |
---|---|
bin | 11011111110010101111010… |
… | …111010000001101001000111 |
3 | 121010121200112211010000211212 |
4 | 123332111322322001221013 |
5 | 112111221301424202401 |
6 | 1113355502304122035 |
7 | 34625503535021612 |
oct | 3376257272015107 |
9 | 533550484100755 |
10 | 123031400225351 |
11 | 36224362006a52 |
12 | 1197038700631b |
13 | 5385a7144bb77 |
14 | 2254a74341179 |
15 | e354e08aedbb |
hex | 6fe57ae81a47 |
123031400225351 has 4 divisors (see below), whose sum is σ = 123031715537712. Its totient is φ = 123031084912992.
The previous prime is 123031400225341. The next prime is 123031400225423. The reversal of 123031400225351 is 153522004130321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123031400225351 - 218 = 123031399963207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123031400225341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157070171 + ... + 157851516.
It is an arithmetic number, because the mean of its divisors is an integer number (30757928884428).
Almost surely, 2123031400225351 is an apocalyptic number.
123031400225351 is a deficient number, since it is larger than the sum of its proper divisors (315312361).
123031400225351 is an equidigital number, since it uses as much as digits as its factorization.
123031400225351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 315312360.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 123031400225351 its reverse (153522004130321), we get a palindrome (276553404355672).
The spelling of 123031400225351 in words is "one hundred twenty-three trillion, thirty-one billion, four hundred million, two hundred twenty-five thousand, three hundred fifty-one".
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