1230403424441 has 2 divisors, whose sum is σ = 1230403424442. Its totient is φ = 1230403424440.

The previous prime is 1230403424359. The next prime is 1230403424473. The reversal of 1230403424441 is 1444243040321.

It is an a-pointer prime, because the next prime (1230403424473) can be obtained adding 1230403424441 to its sum of digits (32).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1138533814441 + 91869610000 = 1067021^2 + 303100^2 .

It is a cyclic number.

It is not a de Polignac number, because 1230403424441 - 2²⁶ = 1230336315577 is a prime.

It is a super-3 number, since 3×1230403424441³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1230403424398 and 1230403424407.

It is not a weakly prime, because it can be changed into another prime (1230403421441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615201712220 + 615201712221.

It is an arithmetic number, because the mean of its divisors is an integer number (615201712221).

Almost surely, 2^{1230403424441} is an apocalyptic number.

It is an amenable number.

1230403424441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1230403424441 is an equidigital number, since it uses as much as digits as its factorization.

1230403424441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36864, while the sum is 32.

Adding to 1230403424441 its reverse (1444243040321), we get a palindrome (2674646464762).

The spelling of 1230403424441 in words is "one trillion, two hundred thirty billion, four hundred three million, four hundred twenty-four thousand, four hundred forty-one".