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123041140321 = 1111185558211
BaseRepresentation
bin111001010010111010…
…0101100111001100001
3102202120221121112202011
41302211310230321201
54003442012442241
6132305130352521
711614034302501
oct1624564547141
9382527545664
10123041140321
11481aa574930
121ba1a28b741
13b7ab274498
145d531bba01
153301e74281
hex1ca5d2ce61

123041140321 has 4 divisors (see below), whose sum is σ = 134226698544. Its totient is φ = 111855582100.

The previous prime is 123041140301. The next prime is 123041140351.

123041140321 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123041140321 is a prime.

It is a super-2 number, since 2×1230411403212 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 123041140292 and 123041140301.

It is not an unprimeable number, because it can be changed into a prime (123041140301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5592779095 + ... + 5592779116.

It is an arithmetic number, because the mean of its divisors is an integer number (33556674636).

Almost surely, 2123041140321 is an apocalyptic number.

123041140321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

123041140321 is a deficient number, since it is larger than the sum of its proper divisors (11185558223).

123041140321 is a wasteful number, since it uses less digits than its factorization.

123041140321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11185558222.

The product of its (nonzero) digits is 576, while the sum is 22.

It can be divided in two parts, 123041 and 140321, that added together give a palindrome (263362).

The spelling of 123041140321 in words is "one hundred twenty-three billion, forty-one million, one hundred forty thousand, three hundred twenty-one".

Divisors: 1 11 11185558211 123041140321