12304402113 has 4 divisors (see below), whose sum is σ = 16405869488. Its totient is φ = 8202934740.

The previous prime is 12304402079. The next prime is 12304402127. The reversal of 12304402113 is 31120440321.

12304402113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31120440321 = 3 ⋅10373480107.

It is not a de Polignac number, because 12304402113 - 2²⁴ = 12287624897 is a prime.

It is a super-2 number, since 2×12304402113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12304402113.

It is not an unprimeable number, because it can be changed into a prime (12304402163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2050733683 + ... + 2050733688.

It is an arithmetic number, because the mean of its divisors is an integer number (4101467372).

Almost surely, 2^12304402113 is an apocalyptic number.

It is an amenable number.

12304402113 is a deficient number, since it is larger than the sum of its proper divisors (4101467375).

12304402113 is an equidigital number, since it uses as much as digits as its factorization.

12304402113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4101467374.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 12304402113 its reverse (31120440321), we get a palindrome (43424842434).

The spelling of 12304402113 in words is "twelve billion, three hundred four million, four hundred two thousand, one hundred thirteen".