123044111251340 has 24 divisors (see below), whose sum is σ = 258393297713040. Its totient is φ = 49217518008128.

The previous prime is 123044111251331. The next prime is 123044111251367. The reversal of 123044111251340 is 43152111440321.

It is a junction number, because it is equal to n+sod(n) for n = 123044111251297 and 123044111251306.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 277271 + ... + 15689649.

It is an arithmetic number, because the mean of its divisors is an integer number (10766387404710).

Almost surely, 2^{123044111251340} is an apocalyptic number.

123044111251340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

123044111251340 is an abundant number, since it is smaller than the sum of its proper divisors (135349186461700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

123044111251340 is a wasteful number, since it uses less digits than its factorization.

123044111251340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15811561 (or 15811559 counting only the distinct ones).

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 123044111251340 its reverse (43152111440321), we get a palindrome (166196222691661).

The spelling of 123044111251340 in words is "one hundred twenty-three trillion, forty-four billion, one hundred eleven million, two hundred fifty-one thousand, three hundred forty".