123044111251381 has 2 divisors, whose sum is σ = 123044111251382. Its totient is φ = 123044111251380.

The previous prime is 123044111251367. The next prime is 123044111251423. The reversal of 123044111251381 is 183152111440321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74922613966225 + 48121497285156 = 8655785^2 + 6936966^2 .

It is an emirp because it is prime and its reverse (183152111440321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123044111251381 - 2¹³ = 123044111243189 is a prime.

It is a super-4 number, since 4×123044111251381⁴ (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 123044111251381.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123044111251331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61522055625690 + 61522055625691.

It is an arithmetic number, because the mean of its divisors is an integer number (61522055625691).

Almost surely, 2^{123044111251381} is an apocalyptic number.

It is an amenable number.

123044111251381 is a deficient number, since it is larger than the sum of its proper divisors (1).

123044111251381 is an equidigital number, since it uses as much as digits as its factorization.

123044111251381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 37.

The spelling of 123044111251381 in words is "one hundred twenty-three trillion, forty-four billion, one hundred eleven million, two hundred fifty-one thousand, three hundred eighty-one".