123044300050141 has 4 divisors (see below), whose sum is σ = 123044590610784. Its totient is φ = 123044009489500.

The previous prime is 123044300050103. The next prime is 123044300050153. The reversal of 123044300050141 is 141050003440321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-123044300050141 is a prime.

It is a super-2 number, since 2×123044300050141² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123044300050181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144644185 + ... + 145492366.

It is an arithmetic number, because the mean of its divisors is an integer number (30761147652696).

Almost surely, 2^{123044300050141} is an apocalyptic number.

It is an amenable number.

123044300050141 is a deficient number, since it is larger than the sum of its proper divisors (290560643).

123044300050141 is an equidigital number, since it uses as much as digits as its factorization.

123044300050141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 290560642.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 123044300050141 its reverse (141050003440321), we get a palindrome (264094303490462).

The spelling of 123044300050141 in words is "one hundred twenty-three trillion, forty-four billion, three hundred million, fifty thousand, one hundred forty-one".