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1230541405553 is a prime number
BaseRepresentation
bin10001111010000001111…
…110111011110101110001
311100122020112202021011002
4101322001332323311301
5130130122044434203
62341145232531345
7154621651236515
oct21720176736561
94318215667132
101230541405553
114349625a8129
1217a5a19b0b55
138c068ba1405
14437b6826145
152202110ad88
hex11e81fbbd71

1230541405553 has 2 divisors, whose sum is σ = 1230541405554. Its totient is φ = 1230541405552.

The previous prime is 1230541405531. The next prime is 1230541405591. The reversal of 1230541405553 is 3555041450321.

It is an a-pointer prime, because the next prime (1230541405591) can be obtained adding 1230541405553 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1215742196449 + 14799209104 = 1102607^2 + 121652^2 .

It is a cyclic number.

It is not a de Polignac number, because 1230541405553 - 210 = 1230541404529 is a prime.

It is not a weakly prime, because it can be changed into another prime (1230541405153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615270702776 + 615270702777.

It is an arithmetic number, because the mean of its divisors is an integer number (615270702777).

Almost surely, 21230541405553 is an apocalyptic number.

It is an amenable number.

1230541405553 is a deficient number, since it is larger than the sum of its proper divisors (1).

1230541405553 is an equidigital number, since it uses as much as digits as its factorization.

1230541405553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180000, while the sum is 38.

Adding to 1230541405553 its reverse (3555041450321), we get a palindrome (4785582855874).

The spelling of 1230541405553 in words is "one trillion, two hundred thirty billion, five hundred forty-one million, four hundred five thousand, five hundred fifty-three".