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123054413250041 = 7131352246299451
BaseRepresentation
bin11011111110101011010110…
…100101101111110111111001
3121010200212221122011210221122
4123332223112211233313321
5112112110414243000131
61113414230025115025
734630250034346220
oct3376532645576771
9533625848153848
10123054413250041
11362330a1292019
121197492a028a75
135387c9b11b540
142255c1885dcb7
15e35ddade3d7b
hex6fead696fdf9

123054413250041 has 8 divisors (see below), whose sum is σ = 151451585538624. Its totient is φ = 97361733560400.

The previous prime is 123054413250031. The next prime is 123054413250161. The reversal of 123054413250041 is 140052314450321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123054413250041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123054413249983 and 123054413250010.

It is not an unprimeable number, because it can be changed into a prime (123054413250001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 676123149635 + ... + 676123149816.

It is an arithmetic number, because the mean of its divisors is an integer number (18931448192328).

Almost surely, 2123054413250041 is an apocalyptic number.

It is an amenable number.

123054413250041 is a deficient number, since it is larger than the sum of its proper divisors (28397172288583).

123054413250041 is a wasteful number, since it uses less digits than its factorization.

123054413250041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1352246299471.

The product of its (nonzero) digits is 57600, while the sum is 35.

The spelling of 123054413250041 in words is "one hundred twenty-three trillion, fifty-four billion, four hundred thirteen million, two hundred fifty thousand, forty-one".

Divisors: 1 7 13 91 1352246299451 9465724096157 17579201892863 123054413250041