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12305877850333 is a prime number
BaseRepresentation
bin1011001100010010111101…
…1110100101100011011101
31121120102121210012212101001
42303010233132211203131
53103104414212202313
642101124153550301
72410033060566634
oct263045736454335
947512553185331
1012305877850333
113a14991262051
121468b65715391
136b35931b9a32
1430787161451b
15165186639add
hexb312f7a58dd

12305877850333 has 2 divisors, whose sum is σ = 12305877850334. Its totient is φ = 12305877850332.

The previous prime is 12305877850309. The next prime is 12305877850369. The reversal of 12305877850333 is 33305877850321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11854269658009 + 451608192324 = 3443003^2 + 672018^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12305877850333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12305877850433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6152938925166 + 6152938925167.

It is an arithmetic number, because the mean of its divisors is an integer number (6152938925167).

Almost surely, 212305877850333 is an apocalyptic number.

It is an amenable number.

12305877850333 is a deficient number, since it is larger than the sum of its proper divisors (1).

12305877850333 is an equidigital number, since it uses as much as digits as its factorization.

12305877850333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12700800, while the sum is 55.

The spelling of 12305877850333 in words is "twelve trillion, three hundred five billion, eight hundred seventy-seven million, eight hundred fifty thousand, three hundred thirty-three".