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12310224140000 = 25545323349843
BaseRepresentation
bin1011001100100011001010…
…0010010111011011100000
31121120211211200112020221102
42303020302202113123200
53103142314334440000
642103123334013532
72410245554465243
oct263106242273340
947524750466842
1012310224140000
113a16811666886
1214699791a72a8
136b3b06795877
14307b6494b25a
1516533ceb43d5
hexb32328976e0

12310224140000 has 240 divisors, whose sum is σ = 30989465659152. Its totient is φ = 4810351104000.

The previous prime is 12310224139963. The next prime is 12310224140033. The reversal of 12310224140000 is 4142201321.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 246955079 + ... + 247004921.

Almost surely, 212310224140000 is an apocalyptic number.

12310224140000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12310224140000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15494732829576).

12310224140000 is an abundant number, since it is smaller than the sum of its proper divisors (18679241519152).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12310224140000 is an equidigital number, since it uses as much as digits as its factorization.

12310224140000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50159 (or 50136 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 12310224140000 its reverse (4142201321), we get a palindrome (12314366341321).

The spelling of 12310224140000 in words is "twelve trillion, three hundred ten billion, two hundred twenty-four million, one hundred forty thousand".