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123102330433 is a prime number
BaseRepresentation
bin111001010100101111…
…0000111111001000001
3102202202012202022210121
41302221132013321001
54004103144033213
6132315154100241
711615406354355
oct1625136077101
9382665668717
10123102330433
1148231068975
121ba3687a681
13b7bab4a054
145d5b389465
15330750e88d
hex1ca9787e41

123102330433 has 2 divisors, whose sum is σ = 123102330434. Its totient is φ = 123102330432.

The previous prime is 123102330431. The next prime is 123102330473. The reversal of 123102330433 is 334033201321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86822747649 + 36279582784 = 294657^2 + 190472^2 .

It is a cyclic number.

It is not a de Polignac number, because 123102330433 - 21 = 123102330431 is a prime.

Together with 123102330431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 123102330398 and 123102330407.

It is not a weakly prime, because it can be changed into another prime (123102330431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61551165216 + 61551165217.

It is an arithmetic number, because the mean of its divisors is an integer number (61551165217).

Almost surely, 2123102330433 is an apocalyptic number.

It is an amenable number.

123102330433 is a deficient number, since it is larger than the sum of its proper divisors (1).

123102330433 is an equidigital number, since it uses as much as digits as its factorization.

123102330433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 123102330433 its reverse (334033201321), we get a palindrome (457135531754).

The spelling of 123102330433 in words is "one hundred twenty-three billion, one hundred two million, three hundred thirty thousand, four hundred thirty-three".