Base | Representation |
---|---|
bin | 11011111111011000111000… |
… | …101101001010111000001011 |
3 | 121010212120010220202101210211 |
4 | 123333120320231022320023 |
5 | 112113411031311044313 |
6 | 1113452513243421551 |
7 | 34633630430033635 |
oct | 3377307055127013 |
9 | 533776126671724 |
10 | 123103304003083 |
11 | 362518aa8a4448 |
12 | 119822b35248b7 |
13 | 538c790120701 |
14 | 2258335b25a55 |
15 | e372ed1c7e3d |
hex | 6ff638b4ae0b |
123103304003083 has 2 divisors, whose sum is σ = 123103304003084. Its totient is φ = 123103304003082.
The previous prime is 123103304003081. The next prime is 123103304003117. The reversal of 123103304003083 is 380300403301321.
It is a weak prime.
It is an emirp because it is prime and its reverse (380300403301321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123103304003083 - 21 = 123103304003081 is a prime.
Together with 123103304003081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (123103304003081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61551652001541 + 61551652001542.
It is an arithmetic number, because the mean of its divisors is an integer number (61551652001542).
Almost surely, 2123103304003083 is an apocalyptic number.
123103304003083 is a deficient number, since it is larger than the sum of its proper divisors (1).
123103304003083 is an equidigital number, since it uses as much as digits as its factorization.
123103304003083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 31.
The spelling of 123103304003083 in words is "one hundred twenty-three trillion, one hundred three billion, three hundred four million, three thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •