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123105232434353 = 139469633264181
BaseRepresentation
bin11011111111011010101011…
…101001100011010010110001
3121010212202010022102212012012
4123333122223221203102301
5112113424004000344403
61113453432452412305
734634026264316351
oct3377325351432261
9533782108385165
10123105232434353
11362526aa3a93a4
1211982751317095
13538ca097ca1c0
142258479cb0b61
15e373b264eed8
hex6ff6aba634b1

123105232434353 has 4 divisors (see below), whose sum is σ = 132574865698548. Its totient is φ = 113635599170160.

The previous prime is 123105232434341. The next prime is 123105232434377. The reversal of 123105232434353 is 353434232501321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 34857770978209 + 88247461456144 = 5904047^2 + 9394012^2 .

It is a cyclic number.

It is not a de Polignac number, because 123105232434353 - 216 = 123105232368817 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 123105232434353.

It is not an unprimeable number, because it can be changed into a prime (123105232434553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4734816632078 + ... + 4734816632103.

It is an arithmetic number, because the mean of its divisors is an integer number (33143716424637).

Almost surely, 2123105232434353 is an apocalyptic number.

123105232434353 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

123105232434353 is a deficient number, since it is larger than the sum of its proper divisors (9469633264195).

123105232434353 is an equidigital number, since it uses as much as digits as its factorization.

123105232434353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9469633264194.

The product of its (nonzero) digits is 777600, while the sum is 41.

Adding to 123105232434353 its reverse (353434232501321), we get a palindrome (476539464935674).

The spelling of 123105232434353 in words is "one hundred twenty-three trillion, one hundred five billion, two hundred thirty-two million, four hundred thirty-four thousand, three hundred fifty-three".

Divisors: 1 13 9469633264181 123105232434353