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1231103299981 is a prime number
BaseRepresentation
bin10001111010100011011…
…110011001000110001101
311100200200201001110101211
4101322203132121012031
5130132244421044411
62341321104134421
7154641613250632
oct21724336310615
94320621043354
101231103299981
11435120799795
1217a71a007411
138c128417819
144382b2d0189
15220555ed221
hex11ea379918d

1231103299981 has 2 divisors, whose sum is σ = 1231103299982. Its totient is φ = 1231103299980.

The previous prime is 1231103299963. The next prime is 1231103300027. The reversal of 1231103299981 is 1899923011321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1096774452900 + 134328847081 = 1047270^2 + 366509^2 .

It is an emirp because it is prime and its reverse (1899923011321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1231103299981 - 25 = 1231103299949 is a prime.

It is a super-2 number, since 2×12311032999812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1231103299781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615551649990 + 615551649991.

It is an arithmetic number, because the mean of its divisors is an integer number (615551649991).

Almost surely, 21231103299981 is an apocalyptic number.

It is an amenable number.

1231103299981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1231103299981 is an equidigital number, since it uses as much as digits as its factorization.

1231103299981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 209952, while the sum is 49.

The spelling of 1231103299981 in words is "one trillion, two hundred thirty-one billion, one hundred three million, two hundred ninety-nine thousand, nine hundred eighty-one".