Base | Representation |
---|---|
bin | 1011001100100110110111… |
… | …1010011010100001010111 |
3 | 1121120221102002222102101011 |
4 | 2303021231322122201113 |
5 | 3103201334344043423 |
6 | 42103410241113051 |
7 | 2410312341633352 |
oct | 263115572324127 |
9 | 47527362872334 |
10 | 12311220299863 |
11 | 3a171829a74a1 |
12 | 1469bb6928787 |
13 | 6b3c34c89b84 |
14 | 307c1ad79299 |
15 | 16539a687b0d |
hex | b326de9a857 |
12311220299863 has 2 divisors, whose sum is σ = 12311220299864. Its totient is φ = 12311220299862.
The previous prime is 12311220299813. The next prime is 12311220300073. The reversal of 12311220299863 is 36899202211321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12311220299863 - 229 = 12310683428951 is a prime.
It is a super-2 number, since 2×123112202998632 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12311220299813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155610149931 + 6155610149932.
It is an arithmetic number, because the mean of its divisors is an integer number (6155610149932).
Almost surely, 212311220299863 is an apocalyptic number.
12311220299863 is a deficient number, since it is larger than the sum of its proper divisors (1).
12311220299863 is an equidigital number, since it uses as much as digits as its factorization.
12311220299863 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 49.
The spelling of 12311220299863 in words is "twelve trillion, three hundred eleven billion, two hundred twenty million, two hundred ninety-nine thousand, eight hundred sixty-three".
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