Base | Representation |
---|---|
bin | 10001111010100101000… |
… | …100010100100101111101 |
3 | 11100200202120022222200100 |
4 | 101322211010110211331 |
5 | 130132323241121341 |
6 | 2341323500551313 |
7 | 154642356336333 |
oct | 21724504244575 |
9 | 4320676288610 |
10 | 1231130020221 |
11 | 43513488a032 |
12 | 17a726b52539 |
13 | 8c130b11a0a |
14 | 43830a87b53 |
15 | 22057b2a3b6 |
hex | 11ea511497d |
1231130020221 has 12 divisors (see below), whose sum is σ = 1778897912220. Its totient is φ = 820476888000.
The previous prime is 1231130020213. The next prime is 1231130020259. The reversal of 1231130020221 is 1220200311321.
1231130020221 is a `hidden beast` number, since 12 + 311 + 300 + 20 + 2 + 21 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 73978016121 + 1157152004100 = 271989^2 + 1075710^2 .
It is not a de Polignac number, because 1231130020221 - 23 = 1231130020213 is a prime.
It is a super-2 number, since 2×12311300202212 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1231130020194 and 1231130020203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1231130020261) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 23010030 + ... + 23063471.
It is an arithmetic number, because the mean of its divisors is an integer number (148241492685).
Almost surely, 21231130020221 is an apocalyptic number.
It is an amenable number.
1231130020221 is a deficient number, since it is larger than the sum of its proper divisors (547767891999).
1231130020221 is a wasteful number, since it uses less digits than its factorization.
1231130020221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46076476 (or 46076473 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 1231130020221 its reverse (1220200311321), we get a palindrome (2451330331542).
The spelling of 1231130020221 in words is "one trillion, two hundred thirty-one billion, one hundred thirty million, twenty thousand, two hundred twenty-one".
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