1231132014031 has 8 divisors (see below), whose sum is σ = 1236864512000. Its totient is φ = 1225408263480.

The previous prime is 1231132014019. The next prime is 1231132014107. The reversal of 1231132014031 is 1304102311321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1231132014031 - 2⁵ = 1231132013999 is a prime.

It is a super-2 number, since 2×1231132014031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1231132013993 and 1231132014011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1231132014731) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1904631 + ... + 2467768.

It is an arithmetic number, because the mean of its divisors is an integer number (154608064000).

Almost surely, 2^{1231132014031} is an apocalyptic number.

1231132014031 is a deficient number, since it is larger than the sum of its proper divisors (5732497969).

1231132014031 is a wasteful number, since it uses less digits than its factorization.

1231132014031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4373709.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1231132014031 its reverse (1304102311321), we get a palindrome (2535234325352).

The spelling of 1231132014031 in words is "one trillion, two hundred thirty-one billion, one hundred thirty-two million, fourteen thousand, thirty-one".