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12311332020913 is a prime number
BaseRepresentation
bin1011001100100111010010…
…0100100110001010110001
31121120221200220012102211211
42303021310210212022301
53103202101444132123
642103425311440121
72410315166353612
oct263116444461261
947527626172754
1012311332020913
113a1722aa74142
12146a028226041
136b3c521756c3
14307c2bb3bc09
151653a53a540d
hexb32749262b1

12311332020913 has 2 divisors, whose sum is σ = 12311332020914. Its totient is φ = 12311332020912.

The previous prime is 12311332020907. The next prime is 12311332020943. The reversal of 12311332020913 is 31902023311321.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10549296129024 + 1762035891889 = 3247968^2 + 1327417^2 .

It is an emirp because it is prime and its reverse (31902023311321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12311332020913 - 25 = 12311332020881 is a prime.

It is a super-3 number, since 3×123113320209133 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12311332020943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155666010456 + 6155666010457.

It is an arithmetic number, because the mean of its divisors is an integer number (6155666010457).

Almost surely, 212311332020913 is an apocalyptic number.

It is an amenable number.

12311332020913 is a deficient number, since it is larger than the sum of its proper divisors (1).

12311332020913 is an equidigital number, since it uses as much as digits as its factorization.

12311332020913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 31.

The spelling of 12311332020913 in words is "twelve trillion, three hundred eleven billion, three hundred thirty-two million, twenty thousand, nine hundred thirteen".