1231133310131 has 2 divisors, whose sum is σ = 1231133310132. Its totient is φ = 1231133310130.

The previous prime is 1231133310119. The next prime is 1231133310163. The reversal of 1231133310131 is 1310133311321.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1231133310131 is a prime.

It is a super-4 number, since 4×1231133310131⁴ (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1231133310097 and 1231133310106.

It is not a weakly prime, because it can be changed into another prime (1231133310181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615566655065 + 615566655066.

It is an arithmetic number, because the mean of its divisors is an integer number (615566655066).

Almost surely, 2^{1231133310131} is an apocalyptic number.

1231133310131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1231133310131 is an equidigital number, since it uses as much as digits as its factorization.

1231133310131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1231133310131 its reverse (1310133311321), we get a palindrome (2541266621452).

The spelling of 1231133310131 in words is "one trillion, two hundred thirty-one billion, one hundred thirty-three million, three hundred ten thousand, one hundred thirty-one".