Base | Representation |
---|---|
bin | 1011001100101001110111… |
… | …0001001111010101110111 |
3 | 1121121000111001210000212121 |
4 | 2303022131301033111313 |
5 | 3103210010414414033 |
6 | 42104022042100411 |
7 | 2410341261322411 |
oct | 263123561172567 |
9 | 47530431700777 |
10 | 12312023201143 |
11 | 3a1755513a076 |
12 | 146a19b7aa707 |
13 | 6b40324174a3 |
14 | 307c9585b9b1 |
15 | 1653e5dd462d |
hex | b329dc4f577 |
12312023201143 has 2 divisors, whose sum is σ = 12312023201144. Its totient is φ = 12312023201142.
The previous prime is 12312023201099. The next prime is 12312023201189. The reversal of 12312023201143 is 34110232021321.
It is a weak prime.
It is an emirp because it is prime and its reverse (34110232021321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12312023201143 - 217 = 12312023070071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12312023231143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156011600571 + 6156011600572.
It is an arithmetic number, because the mean of its divisors is an integer number (6156011600572).
Almost surely, 212312023201143 is an apocalyptic number.
12312023201143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12312023201143 is an equidigital number, since it uses as much as digits as its factorization.
12312023201143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 12312023201143 its reverse (34110232021321), we get a palindrome (46422255222464).
The spelling of 12312023201143 in words is "twelve trillion, three hundred twelve billion, twenty-three million, two hundred one thousand, one hundred forty-three".
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