Base | Representation |
---|---|
bin | 11011111111101001100101… |
… | …111011010001010101011010 |
3 | 121010221021110002021200001210 |
4 | 123333221211323101111122 |
5 | 112114204301042342300 |
6 | 1113505041252523550 |
7 | 34635134111102304 |
oct | 3377514573212532 |
9 | 533837402250053 |
10 | 123121242543450 |
11 | 36259475719318 |
12 | 1198587b0205b6 |
13 | 539138b6b2838 |
14 | 2259158314974 |
15 | e379ece91050 |
hex | 6ffa65ed155a |
123121242543450 has 96 divisors (see below), whose sum is σ = 307780576228800. Its totient is φ = 32570537126400.
The previous prime is 123121242543353. The next prime is 123121242543577. The reversal of 123121242543450 is 54345242121321.
It is a junction number, because it is equal to n+sod(n) for n = 123121242543399 and 123121242543408.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 14089590 + ... + 21089310.
It is an arithmetic number, because the mean of its divisors is an integer number (3206047669050).
Almost surely, 2123121242543450 is an apocalyptic number.
123121242543450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 123121242543450, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (153890288114400).
123121242543450 is an abundant number, since it is smaller than the sum of its proper divisors (184659333685350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
123121242543450 is a wasteful number, since it uses less digits than its factorization.
123121242543450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7000672 (or 7000667 counting only the distinct ones).
The product of its (nonzero) digits is 230400, while the sum is 39.
Adding to 123121242543450 its reverse (54345242121321), we get a palindrome (177466484664771).
The spelling of 123121242543450 in words is "one hundred twenty-three trillion, one hundred twenty-one billion, two hundred forty-two million, five hundred forty-three thousand, four hundred fifty".
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