Base | Representation |
---|---|
bin | 10110111011110100… |
… | …11010001110011111 |
3 | 1011210010002202212021 |
4 | 23131322122032133 |
5 | 200204112323403 |
6 | 5353450321011 |
7 | 614061603361 |
oct | 133572321637 |
9 | 34703082767 |
10 | 12313011103 |
11 | 5249412538 |
12 | 2477729167 |
13 | 1212c698b3 |
14 | 84b41ad31 |
15 | 4c0e9e8bd |
hex | 2dde9a39f |
12313011103 has 2 divisors, whose sum is σ = 12313011104. Its totient is φ = 12313011102.
The previous prime is 12313011013. The next prime is 12313011121. The reversal of 12313011103 is 30111031321.
Together with previous prime (12313011013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12313011103 - 225 = 12279456671 is a prime.
It is a super-2 number, since 2×123130111032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313011173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156505551 + 6156505552.
It is an arithmetic number, because the mean of its divisors is an integer number (6156505552).
Almost surely, 212313011103 is an apocalyptic number.
12313011103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313011103 is an equidigital number, since it uses as much as digits as its factorization.
12313011103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 12313011103 its reverse (30111031321), we get a palindrome (42424042424).
The spelling of 12313011103 in words is "twelve billion, three hundred thirteen million, eleven thousand, one hundred three".
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