Search a number
-
+
123130131030133 = 402517305900449
BaseRepresentation
bin11011111111110001110111…
…101110001010000001110101
3121010222010101112112120120021
4123333301313232022001311
5112114331002020431013
61113513111252005141
734635600301016533
oct3377616756120165
9533863345476507
10123130131030133
1136262216a74987
121198753b9007b1
13539217701aa06
14225975c9bd153
15e37d6d491a8d
hex6ffc77b8a075

123130131030133 has 4 divisors (see below), whose sum is σ = 123130437333100. Its totient is φ = 123129824727168.

The previous prime is 123130131030079. The next prime is 123130131030143. The reversal of 123130131030133 is 331030131031321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 56693400368004 + 66436730662129 = 7529502^2 + 8150873^2 .

It is a cyclic number.

It is not a de Polignac number, because 123130131030133 - 29 = 123130131029621 is a prime.

It is a super-2 number, since 2×1231301310301332 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 123130131030098 and 123130131030107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123130131030143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152547708 + ... + 153352741.

It is an arithmetic number, because the mean of its divisors is an integer number (30782609333275).

Almost surely, 2123130131030133 is an apocalyptic number.

It is an amenable number.

123130131030133 is a deficient number, since it is larger than the sum of its proper divisors (306302967).

123130131030133 is an equidigital number, since it uses as much as digits as its factorization.

123130131030133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 306302966.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 123130131030133 its reverse (331030131031321), we get a palindrome (454160262061454).

The spelling of 123130131030133 in words is "one hundred twenty-three trillion, one hundred thirty billion, one hundred thirty-one million, thirty thousand, one hundred thirty-three".

Divisors: 1 402517 305900449 123130131030133