Base | Representation |
---|---|
bin | 10110111011110101… |
… | …10010101000110101 |
3 | 1011210010021212000121 |
4 | 23131322302220311 |
5 | 200204124023333 |
6 | 5353452411541 |
7 | 614062501033 |
oct | 133572625065 |
9 | 34703255017 |
10 | 12313111093 |
11 | 5249480678 |
12 | 2477776bb1 |
13 | 1212ca326a |
14 | 84b445553 |
15 | 4c0ebe32d |
hex | 2ddeb2a35 |
12313111093 has 2 divisors, whose sum is σ = 12313111094. Its totient is φ = 12313111092.
The previous prime is 12313111049. The next prime is 12313111121. The reversal of 12313111093 is 39011131321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8071584964 + 4241526129 = 89842^2 + 65127^2 .
It is a cyclic number.
It is not a de Polignac number, because 12313111093 - 29 = 12313110581 is a prime.
It is a super-2 number, since 2×123131110932 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313111693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156555546 + 6156555547.
It is an arithmetic number, because the mean of its divisors is an integer number (6156555547).
Almost surely, 212313111093 is an apocalyptic number.
It is an amenable number.
12313111093 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313111093 is an equidigital number, since it uses as much as digits as its factorization.
12313111093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 12313111093 in words is "twelve billion, three hundred thirteen million, one hundred eleven thousand, ninety-three".
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