Base | Representation |
---|---|
bin | 10001111010101111111… |
… | …111001000101100010011 |
3 | 11100201020100000222222211 |
4 | 101322233333020230103 |
5 | 130133212140211011 |
6 | 2341354003212551 |
7 | 154650042411604 |
oct | 21725777105423 |
9 | 4321210028884 |
10 | 1231313210131 |
11 | 435219230354 |
12 | 17a778377157 |
13 | 8c15ca61804 |
14 | 4384b131dab |
15 | 22068c63b21 |
hex | 11eaffc8b13 |
1231313210131 has 4 divisors (see below), whose sum is σ = 1231318053000. Its totient is φ = 1231308367264.
The previous prime is 1231313210117. The next prime is 1231313210147. The reversal of 1231313210131 is 1310123131321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1231313210131 - 225 = 1231279655699 is a prime.
It is a super-2 number, since 2×12313132101312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1231313210191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2017606 + ... + 2556043.
It is an arithmetic number, because the mean of its divisors is an integer number (307829513250).
Almost surely, 21231313210131 is an apocalyptic number.
1231313210131 is a deficient number, since it is larger than the sum of its proper divisors (4842869).
1231313210131 is an equidigital number, since it uses as much as digits as its factorization.
1231313210131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4842868.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 1231313210131 its reverse (1310123131321), we get a palindrome (2541436341452).
The spelling of 1231313210131 in words is "one trillion, two hundred thirty-one billion, three hundred thirteen million, two hundred ten thousand, one hundred thirty-one".
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