Base | Representation |
---|---|
bin | 111001010101100111… |
… | …1110011101100010001 |
3 | 102202211021211102000112 |
4 | 1302223033303230101 |
5 | 4004133311211423 |
6 | 132322140531105 |
7 | 11616220565624 |
oct | 1625317635421 |
9 | 382737742015 |
10 | 123132132113 |
11 | 48246973361 |
12 | 1ba44850a95 |
13 | b7c4082993 |
14 | 5d61305dbb |
15 | 3309e49a78 |
hex | 1cab3f3b11 |
123132132113 has 2 divisors, whose sum is σ = 123132132114. Its totient is φ = 123132132112.
The previous prime is 123132132073. The next prime is 123132132143. The reversal of 123132132113 is 311231231321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 88337945089 + 34794187024 = 297217^2 + 186532^2 .
It is an emirp because it is prime and its reverse (311231231321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123132132113 - 224 = 123115354897 is a prime.
It is not a weakly prime, because it can be changed into another prime (123132132143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61566066056 + 61566066057.
It is an arithmetic number, because the mean of its divisors is an integer number (61566066057).
Almost surely, 2123132132113 is an apocalyptic number.
It is an amenable number.
123132132113 is a deficient number, since it is larger than the sum of its proper divisors (1).
123132132113 is an equidigital number, since it uses as much as digits as its factorization.
123132132113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 648, while the sum is 23.
Adding to 123132132113 its reverse (311231231321), we get a palindrome (434363363434).
The spelling of 123132132113 in words is "one hundred twenty-three billion, one hundred thirty-two million, one hundred thirty-two thousand, one hundred thirteen".
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