Base | Representation |
---|---|
bin | 1011001100101110101110… |
… | …1110011110111000100111 |
3 | 1121121010212012211020111022 |
4 | 2303023223232132320213 |
5 | 3103220200230214343 |
6 | 42104355523001355 |
7 | 2410415552305235 |
oct | 263135356367047 |
9 | 47533765736438 |
10 | 12313331101223 |
11 | 3a18066442829 |
12 | 146a4a580925b |
13 | 6b41b038a269 |
14 | 307d7b437955 |
15 | 165470b35568 |
hex | b32ebb9ee27 |
12313331101223 has 2 divisors, whose sum is σ = 12313331101224. Its totient is φ = 12313331101222.
The previous prime is 12313331101199. The next prime is 12313331101229. The reversal of 12313331101223 is 32210113331321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12313331101223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12313331101192 and 12313331101201.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313331101229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156665550611 + 6156665550612.
It is an arithmetic number, because the mean of its divisors is an integer number (6156665550612).
Almost surely, 212313331101223 is an apocalyptic number.
12313331101223 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313331101223 is an equidigital number, since it uses as much as digits as its factorization.
12313331101223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 12313331101223 its reverse (32210113331321), we get a palindrome (44523444432544).
The spelling of 12313331101223 in words is "twelve trillion, three hundred thirteen billion, three hundred thirty-one million, one hundred one thousand, two hundred twenty-three".
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