Base | Representation |
---|---|
bin | 10110111011110111… |
… | …11010001011110111 |
3 | 1011210010211202000121 |
4 | 23131323322023313 |
5 | 200204212413101 |
6 | 5353502552411 |
7 | 614065131316 |
oct | 133573721367 |
9 | 34703752017 |
10 | 12313404151 |
11 | 5249660874 |
12 | 2477898707 |
13 | 1213076779 |
14 | 84b4c027d |
15 | 4c102b0a1 |
hex | 2ddefa2f7 |
12313404151 has 2 divisors, whose sum is σ = 12313404152. Its totient is φ = 12313404150.
The previous prime is 12313404127. The next prime is 12313404203. The reversal of 12313404151 is 15140431321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12313404151 - 217 = 12313273079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313405151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156702075 + 6156702076.
It is an arithmetic number, because the mean of its divisors is an integer number (6156702076).
Almost surely, 212313404151 is an apocalyptic number.
12313404151 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313404151 is an equidigital number, since it uses as much as digits as its factorization.
12313404151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 12313404151 its reverse (15140431321), we get a palindrome (27453835472).
The spelling of 12313404151 in words is "twelve billion, three hundred thirteen million, four hundred four thousand, one hundred fifty-one".
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