Base | Representation |
---|---|
bin | 11011111111110101110001… |
… | …101001100001111100111011 |
3 | 121010222112012202120200102221 |
4 | 123333311301221201330323 |
5 | 112114413043433341103 |
6 | 1113515043320304511 |
7 | 34636106224504450 |
oct | 3377656151417473 |
9 | 533875182520387 |
10 | 123134324121403 |
11 | 36263a78952471 |
12 | 11988310012137 |
13 | 5392694947bca |
14 | 2259a39837827 |
15 | e380166591bd |
hex | 6ffd71a61f3b |
123134324121403 has 64 divisors (see below), whose sum is σ = 145508097208320. Its totient is φ = 102009922560000.
The previous prime is 123134324121373. The next prime is 123134324121439. The reversal of 123134324121403 is 304121423431321.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-123134324121403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (123134324121443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19357695943 + ... + 19357702303.
It is an arithmetic number, because the mean of its divisors is an integer number (2273564018880).
Almost surely, 2123134324121403 is an apocalyptic number.
123134324121403 is a deficient number, since it is larger than the sum of its proper divisors (22373773086917).
123134324121403 is a wasteful number, since it uses less digits than its factorization.
123134324121403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8060.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 123134324121403 its reverse (304121423431321), we get a palindrome (427255747552724).
The spelling of 123134324121403 in words is "one hundred twenty-three trillion, one hundred thirty-four billion, three hundred twenty-four million, one hundred twenty-one thousand, four hundred three".
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