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12314005153 = 15181549703
BaseRepresentation
bin10110111011111100…
…01100111010100001
31011210011222021102221
423131332030322201
5200204341131103
65353523511041
7614103213442
oct133576147241
934704867387
1012314005153
115249a3136a
122477b28481
1312132271a8
1484b5d92c9
154c10e91bd
hex2ddf8cea1

12314005153 has 4 divisors (see below), whose sum is σ = 12395555008. Its totient is φ = 12232455300.

The previous prime is 12314005147. The next prime is 12314005183. The reversal of 12314005153 is 35150041321.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35150041321 = 41857318081.

It is a cyclic number.

It is not a de Polignac number, because 12314005153 - 221 = 12311908001 is a prime.

It is a super-2 number, since 2×123140051532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12314005133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40774701 + ... + 40775002.

It is an arithmetic number, because the mean of its divisors is an integer number (3098888752).

Almost surely, 212314005153 is an apocalyptic number.

It is an amenable number.

12314005153 is a deficient number, since it is larger than the sum of its proper divisors (81549855).

12314005153 is an equidigital number, since it uses as much as digits as its factorization.

12314005153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81549854.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 12314005153 its reverse (35150041321), we get a palindrome (47464046474).

The spelling of 12314005153 in words is "twelve billion, three hundred fourteen million, five thousand, one hundred fifty-three".

Divisors: 1 151 81549703 12314005153