Base | Representation |
---|---|
bin | 11011111111111011010001… |
… | …110111110011011101001111 |
3 | 121011000002110121000022221101 |
4 | 123333323101313303131033 |
5 | 112120012144230140101 |
6 | 1113521501533443531 |
7 | 34636405531063651 |
oct | 3377732167633517 |
9 | 534002417008841 |
10 | 123140233443151 |
11 | 36266530579351 |
12 | 1198949b0405a7 |
13 | 53930c6cb50b2 |
14 | 225a03a5a06d1 |
15 | e3826032e401 |
hex | 6ffed1df374f |
123140233443151 has 2 divisors, whose sum is σ = 123140233443152. Its totient is φ = 123140233443150.
The previous prime is 123140233443133. The next prime is 123140233443239. The reversal of 123140233443151 is 151344332041321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123140233443151 - 223 = 123140225054543 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 123140233443151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123140233449151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61570116721575 + 61570116721576.
It is an arithmetic number, because the mean of its divisors is an integer number (61570116721576).
Almost surely, 2123140233443151 is an apocalyptic number.
123140233443151 is a deficient number, since it is larger than the sum of its proper divisors (1).
123140233443151 is an equidigital number, since it uses as much as digits as its factorization.
123140233443151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 123140233443151 its reverse (151344332041321), we get a palindrome (274484565484472).
The spelling of 123140233443151 in words is "one hundred twenty-three trillion, one hundred forty billion, two hundred thirty-three million, four hundred forty-three thousand, one hundred fifty-one".
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