Base | Representation |
---|---|
bin | 10001111010110110000… |
… | …101000101101100010101 |
3 | 11100201111110101111210020 |
4 | 101322312011011230111 |
5 | 130133414322342010 |
6 | 2341412054215353 |
7 | 154652423325441 |
oct | 21726605055425 |
9 | 4321443344706 |
10 | 1231415434005 |
11 | 435270a00699 |
12 | 17a7a6654559 |
13 | 8c177ca3603 |
14 | 4385a941821 |
15 | 22072c07470 |
hex | 11eb6145b15 |
1231415434005 has 16 divisors (see below), whose sum is σ = 1970444024640. Its totient is φ = 656695121408.
The previous prime is 1231415433953. The next prime is 1231415434037. The reversal of 1231415434005 is 5004345141321.
It is a cyclic number.
It is not a de Polignac number, because 1231415434005 - 219 = 1231414909717 is a prime.
It is a super-2 number, since 2×12314154340052 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3565500 + ... + 3895589.
It is an arithmetic number, because the mean of its divisors is an integer number (123152751540).
Almost surely, 21231415434005 is an apocalyptic number.
1231415434005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1231415434005 is a deficient number, since it is larger than the sum of its proper divisors (739028590635).
1231415434005 is a wasteful number, since it uses less digits than its factorization.
1231415434005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7472100.
The product of its (nonzero) digits is 28800, while the sum is 33.
The spelling of 1231415434005 in words is "one trillion, two hundred thirty-one billion, four hundred fifteen million, four hundred thirty-four thousand, five".
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