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1231422143981 is a prime number
BaseRepresentation
bin10001111010110110011…
…110101011110111101101
311100201111221000102010212
4101322312132223313231
5130133423032101411
62341412454112205
7154652534343161
oct21726636536755
94321457012125
101231422143981
11435274773a27
1217a7a894b665
138c1794b2803
144385b7aaca1
15220735d068b
hex11eb67abded

1231422143981 has 2 divisors, whose sum is σ = 1231422143982. Its totient is φ = 1231422143980.

The previous prime is 1231422143971. The next prime is 1231422144023. The reversal of 1231422143981 is 1893412241321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 692873112100 + 538549031881 = 832390^2 + 733859^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1231422143981 is a prime.

It is a super-2 number, since 2×12314221439812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1231422143971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615711071990 + 615711071991.

It is an arithmetic number, because the mean of its divisors is an integer number (615711071991).

Almost surely, 21231422143981 is an apocalyptic number.

It is an amenable number.

1231422143981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1231422143981 is an equidigital number, since it uses as much as digits as its factorization.

1231422143981 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 82944, while the sum is 41.

The spelling of 1231422143981 in words is "one trillion, two hundred thirty-one billion, four hundred twenty-two million, one hundred forty-three thousand, nine hundred eighty-one".