Base | Representation |
---|---|
bin | 10001111010110110011… |
… | …110101011111000000001 |
3 | 11100201111221000102011121 |
4 | 101322312132223320001 |
5 | 130133423032102001 |
6 | 2341412454112241 |
7 | 154652534343220 |
oct | 21726636537001 |
9 | 4321457012147 |
10 | 1231422144001 |
11 | 435274773a45 |
12 | 17a7a894b681 |
13 | 8c1794b281a |
14 | 4385b7aacb7 |
15 | 220735d06a1 |
hex | 11eb67abe01 |
1231422144001 has 4 divisors (see below), whose sum is σ = 1407339593152. Its totient is φ = 1055504694852.
The previous prime is 1231422143981. The next prime is 1231422144023. The reversal of 1231422144001 is 1004412241321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1231422144001 - 25 = 1231422143969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1231422144031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87958724565 + ... + 87958724578.
It is an arithmetic number, because the mean of its divisors is an integer number (351834898288).
Almost surely, 21231422144001 is an apocalyptic number.
It is an amenable number.
1231422144001 is a deficient number, since it is larger than the sum of its proper divisors (175917449151).
1231422144001 is an equidigital number, since it uses as much as digits as its factorization.
1231422144001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 175917449150.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1231422144001 its reverse (1004412241321), we get a palindrome (2235834385322).
The spelling of 1231422144001 in words is "one trillion, two hundred thirty-one billion, four hundred twenty-two million, one hundred forty-four thousand, one".
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