Base | Representation |
---|---|
bin | 10001111010110111000… |
… | …100101010101011000111 |
3 | 11100201112121202020222201 |
4 | 101322313010222223013 |
5 | 130133433104204201 |
6 | 2341413451335331 |
7 | 154653015102112 |
oct | 21726704525307 |
9 | 4321477666881 |
10 | 1231432100551 |
11 | 43527a3544a4 |
12 | 17a7b0151547 |
13 | 8c17b58a683 |
14 | 4385cc3d579 |
15 | 220743ea801 |
hex | 11eb712aac7 |
1231432100551 has 2 divisors, whose sum is σ = 1231432100552. Its totient is φ = 1231432100550.
The previous prime is 1231432100501. The next prime is 1231432100627. The reversal of 1231432100551 is 1550012341321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1231432100551 - 221 = 1231430003399 is a prime.
It is a super-3 number, since 3×12314321005513 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1231432100501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615716050275 + 615716050276.
It is an arithmetic number, because the mean of its divisors is an integer number (615716050276).
Almost surely, 21231432100551 is an apocalyptic number.
1231432100551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1231432100551 is an equidigital number, since it uses as much as digits as its factorization.
1231432100551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 1231432100551 its reverse (1550012341321), we get a palindrome (2781444441872).
The spelling of 1231432100551 in words is "one trillion, two hundred thirty-one billion, four hundred thirty-two million, one hundred thousand, five hundred fifty-one".
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