123143331 has 4 divisors (see below), whose sum is σ = 164191112. Its totient is φ = 82095552.

The previous prime is 123143329. The next prime is 123143333. The reversal of 123143331 is 133341321.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 133341321 = 3 ⋅44447107.

It is an interprime number because it is at equal distance from previous prime (123143329) and next prime (123143333).

It is not a de Polignac number, because 123143331 - 2¹ = 123143329 is a prime.

It is a super-2 number, since 2×123143331² = 30328559939551122, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 123143298 and 123143307.

It is not an unprimeable number, because it can be changed into a prime (123143333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20523886 + ... + 20523891.

It is an arithmetic number, because the mean of its divisors is an integer number (41047778).

Almost surely, 2^123143331 is an apocalyptic number.

123143331 is a deficient number, since it is larger than the sum of its proper divisors (41047781).

123143331 is an equidigital number, since it uses as much as digits as its factorization.

123143331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41047780.

The product of its digits is 648, while the sum is 21.

The square root of 123143331 is about 11096.9964855361. The cubic root of 123143331 is about 497.5120823981.

Adding to 123143331 its reverse (133341321), we get a palindrome (256484652).

The spelling of 123143331 in words is "one hundred twenty-three million, one hundred forty-three thousand, three hundred thirty-one".