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1232002113 = 3410667371
BaseRepresentation
bin100100101101110…
…1101110001000001
310011212020012011220
41021123231301001
510010343031423
6322130025253
742346562616
oct11133556101
93155205156
101232002113
11582484471
122a4718229
1316831a844
14b98a050d
157325c9e3
hex496edc41

1232002113 has 4 divisors (see below), whose sum is σ = 1642669488. Its totient is φ = 821334740.

The previous prime is 1232002111. The next prime is 1232002127. The reversal of 1232002113 is 3112002321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1232002113 - 21 = 1232002111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1232002092 and 1232002101.

It is not an unprimeable number, because it can be changed into a prime (1232002111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205333683 + ... + 205333688.

It is an arithmetic number, because the mean of its divisors is an integer number (410667372).

Almost surely, 21232002113 is an apocalyptic number.

It is an amenable number.

1232002113 is a deficient number, since it is larger than the sum of its proper divisors (410667375).

1232002113 is an equidigital number, since it uses as much as digits as its factorization.

1232002113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 410667374.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 1232002113 is about 35099.8876493928. The cubic root of 1232002113 is about 1072.0222950666.

Adding to 1232002113 its reverse (3112002321), we get a palindrome (4344004434).

The spelling of 1232002113 in words is "one billion, two hundred thirty-two million, two thousand, one hundred thirteen".

Divisors: 1 3 410667371 1232002113