Base | Representation |
---|---|
bin | 1011001101001000011100… |
… | …0000010100100011111101 |
3 | 1121121210200002121020211012 |
4 | 2303102013000110203331 |
5 | 3103323313142311214 |
6 | 42111500332205005 |
7 | 2411051546300135 |
oct | 263220700244375 |
9 | 47553602536735 |
10 | 12320231213309 |
11 | 3a1aa873720a8 |
12 | 146b8b0609765 |
13 | 6b4a3ca8b716 |
14 | 3084339d1ac5 |
15 | 1657267bd03e |
hex | b34870148fd |
12320231213309 has 2 divisors, whose sum is σ = 12320231213310. Its totient is φ = 12320231213308.
The previous prime is 12320231213293. The next prime is 12320231213327. The reversal of 12320231213309 is 90331213202321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12178550489284 + 141680724025 = 3489778^2 + 376405^2 .
It is a cyclic number.
It is not a de Polignac number, because 12320231213309 - 24 = 12320231213293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12320231213809) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160115606654 + 6160115606655.
It is an arithmetic number, because the mean of its divisors is an integer number (6160115606655).
Almost surely, 212320231213309 is an apocalyptic number.
It is an amenable number.
12320231213309 is a deficient number, since it is larger than the sum of its proper divisors (1).
12320231213309 is an equidigital number, since it uses as much as digits as its factorization.
12320231213309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 32.
The spelling of 12320231213309 in words is "twelve trillion, three hundred twenty billion, two hundred thirty-one million, two hundred thirteen thousand, three hundred nine".
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