12320311433 has 2 divisors, whose sum is σ = 12320311434. Its totient is φ = 12320311432.

The previous prime is 12320311403. The next prime is 12320311447. The reversal of 12320311433 is 33411302321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8184278089 + 4136033344 = 90467^2 + 64312^2 .

It is a cyclic number.

It is not a de Polignac number, because 12320311433 - 2¹⁴ = 12320295049 is a prime.

It is a super-2 number, since 2×12320311433² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12320311399 and 12320311408.

It is not a weakly prime, because it can be changed into another prime (12320311403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160155716 + 6160155717.

It is an arithmetic number, because the mean of its divisors is an integer number (6160155717).

Almost surely, 2^12320311433 is an apocalyptic number.

It is an amenable number.

12320311433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12320311433 is an equidigital number, since it uses as much as digits as its factorization.

12320311433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 12320311433 its reverse (33411302321), we get a palindrome (45731613754).

The spelling of 12320311433 in words is "twelve billion, three hundred twenty million, three hundred eleven thousand, four hundred thirty-three".