Base | Representation |
---|---|
bin | 10110111100101101… |
… | …10000001100110111 |
3 | 1011210122002020221221 |
4 | 23132112300030313 |
5 | 200213013104033 |
6 | 5354313451211 |
7 | 614212010323 |
oct | 133626601467 |
9 | 34718066857 |
10 | 12320441143 |
11 | 525262786a |
12 | 247a110b07 |
13 | 121466b77a |
14 | 84c3d2983 |
15 | 4c196b12d |
hex | 2de5b0337 |
12320441143 has 4 divisors (see below), whose sum is σ = 12325579200. Its totient is φ = 12315303088.
The previous prime is 12320441123. The next prime is 12320441213. The reversal of 12320441143 is 34114402321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12320441143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12320441123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2565430 + ... + 2570227.
It is an arithmetic number, because the mean of its divisors is an integer number (3081394800).
Almost surely, 212320441143 is an apocalyptic number.
12320441143 is a deficient number, since it is larger than the sum of its proper divisors (5138057).
12320441143 is an equidigital number, since it uses as much as digits as its factorization.
12320441143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5138056.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12320441143 its reverse (34114402321), we get a palindrome (46434843464).
The spelling of 12320441143 in words is "twelve billion, three hundred twenty million, four hundred forty-one thousand, one hundred forty-three".
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