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123214320043 = 177247901179
BaseRepresentation
bin111001011000000100…
…1010101000110101011
3102210001000110222122221
41302300021111012223
54004320331220133
6132334234254511
711621236303603
oct1626011250653
9383030428587
10123214320043
11482892a9371
121ba68287437
13b8080caba9
145d6c1bbc03
153312281a2d
hex1cb02551ab

123214320043 has 4 divisors (see below), whose sum is σ = 130462221240. Its totient is φ = 115966418848.

The previous prime is 123214320017. The next prime is 123214320049. The reversal of 123214320043 is 340023412321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 123214320043 - 25 = 123214320011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (123214320049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3623950573 + ... + 3623950606.

It is an arithmetic number, because the mean of its divisors is an integer number (32615555310).

Almost surely, 2123214320043 is an apocalyptic number.

123214320043 is a deficient number, since it is larger than the sum of its proper divisors (7247901197).

123214320043 is an equidigital number, since it uses as much as digits as its factorization.

123214320043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7247901196.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 123214320043 its reverse (340023412321), we get a palindrome (463237732364).

The spelling of 123214320043 in words is "one hundred twenty-three billion, two hundred fourteen million, three hundred twenty thousand, forty-three".

Divisors: 1 17 7247901179 123214320043