Base | Representation |
---|---|
bin | 10001111011100001011… |
… | …101101011101000011001 |
3 | 11100210101011222222210110 |
4 | 101323201131223220121 |
5 | 130141412141114040 |
6 | 2342012215034533 |
7 | 155006442153201 |
oct | 21734135535031 |
9 | 4323334888713 |
10 | 1232143301145 |
11 | 435604853a89 |
12 | 17a96a36ba49 |
13 | 8c262a1bc23 |
14 | 438c9491401 |
15 | 220b6a81980 |
hex | 11ee176ba19 |
1232143301145 has 16 divisors (see below), whose sum is σ = 1971489085632. Its totient is φ = 657123159360.
The previous prime is 1232143301141. The next prime is 1232143301153. The reversal of 1232143301145 is 5411033412321.
It is not a de Polignac number, because 1232143301145 - 22 = 1232143301141 is a prime.
It is a super-2 number, since 2×12321433011452 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1232143301141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 728011 + ... + 1730400.
It is an arithmetic number, because the mean of its divisors is an integer number (123218067852).
Almost surely, 21232143301145 is an apocalyptic number.
1232143301145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1232143301145 is a deficient number, since it is larger than the sum of its proper divisors (739345784487).
1232143301145 is a wasteful number, since it uses less digits than its factorization.
1232143301145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2491832.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 1232143301145 its reverse (5411033412321), we get a palindrome (6643176713466).
The spelling of 1232143301145 in words is "one trillion, two hundred thirty-two billion, one hundred forty-three million, three hundred one thousand, one hundred forty-five".
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