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12322200924851 is a prime number
BaseRepresentation
bin1011001101001111110001…
…1010001011001010110011
31121121222202100221222002112
42303103330122023022303
53103341331414043401
642112424014035535
72411151424462316
oct263237432131263
947558670858075
1012322200924851
113a208a8201584
1214701601a8bab
136b4c94b8c6cc
1430857d44497d
151657de69b3bb
hexb34fc68b2b3

12322200924851 has 2 divisors, whose sum is σ = 12322200924852. Its totient is φ = 12322200924850.

The previous prime is 12322200924841. The next prime is 12322200924853. The reversal of 12322200924851 is 15842900222321.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12322200924851 is a prime.

Together with 12322200924853, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12322200924799 and 12322200924808.

It is not a weakly prime, because it can be changed into another prime (12322200924853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6161100462425 + 6161100462426.

It is an arithmetic number, because the mean of its divisors is an integer number (6161100462426).

Almost surely, 212322200924851 is an apocalyptic number.

12322200924851 is a deficient number, since it is larger than the sum of its proper divisors (1).

12322200924851 is an equidigital number, since it uses as much as digits as its factorization.

12322200924851 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 138240, while the sum is 41.

The spelling of 12322200924851 in words is "twelve trillion, three hundred twenty-two billion, two hundred million, nine hundred twenty-four thousand, eight hundred fifty-one".