Base | Representation |
---|---|
bin | 1011001101001111110110… |
… | …0010111100001101110001 |
3 | 1121121222210200212002102201 |
4 | 2303103331202330031301 |
5 | 3103341401310000423 |
6 | 42112425534543201 |
7 | 2411152045560322 |
oct | 263237542741561 |
9 | 47558720762381 |
10 | 12322220000113 |
11 | 3a20907a50061 |
12 | 1470166667b01 |
13 | 6b4c98b0ac4a |
14 | 308581bac449 |
15 | 1657e11b82ad |
hex | b34fd8bc371 |
12322220000113 has 2 divisors, whose sum is σ = 12322220000114. Its totient is φ = 12322220000112.
The previous prime is 12322220000071. The next prime is 12322220000171. The reversal of 12322220000113 is 31100002222321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7891733863729 + 4430486136384 = 2809223^2 + 2104872^2 .
It is a cyclic number.
It is not a de Polignac number, because 12322220000113 - 217 = 12322219869041 is a prime.
It is not a weakly prime, because it can be changed into another prime (12322220000213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6161110000056 + 6161110000057.
It is an arithmetic number, because the mean of its divisors is an integer number (6161110000057).
Almost surely, 212322220000113 is an apocalyptic number.
It is an amenable number.
12322220000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12322220000113 is an equidigital number, since it uses as much as digits as its factorization.
12322220000113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 12322220000113 its reverse (31100002222321), we get a palindrome (43422222222434).
The spelling of 12322220000113 in words is "twelve trillion, three hundred twenty-two billion, two hundred twenty million, one hundred thirteen", and thus it is an aban number.
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