Base | Representation |
---|---|
bin | 11100000001001111111011… |
… | …001100110100010111100111 |
3 | 121011022210001201020020211211 |
4 | 130001033323030310113213 |
5 | 112123004314002142413 |
6 | 1114031332344212251 |
7 | 34646104026506455 |
oct | 3401177314642747 |
9 | 534283051206754 |
10 | 123231121130983 |
11 | 362a1030282448 |
12 | 119a302516a087 |
13 | 539b84c9ac938 |
14 | 22605bd3319d5 |
15 | e3a7ce5a483d |
hex | 7013fb3345e7 |
123231121130983 has 2 divisors, whose sum is σ = 123231121130984. Its totient is φ = 123231121130982.
The previous prime is 123231121130969. The next prime is 123231121131103. The reversal of 123231121130983 is 389031121132321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123231121130983 - 25 = 123231121130951 is a prime.
It is a super-2 number, since 2×1232311211309832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123231121130933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61615560565491 + 61615560565492.
It is an arithmetic number, because the mean of its divisors is an integer number (61615560565492).
Almost surely, 2123231121130983 is an apocalyptic number.
123231121130983 is a deficient number, since it is larger than the sum of its proper divisors (1).
123231121130983 is an equidigital number, since it uses as much as digits as its factorization.
123231121130983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 40.
The spelling of 123231121130983 in words is "one hundred twenty-three trillion, two hundred thirty-one billion, one hundred twenty-one million, one hundred thirty thousand, nine hundred eighty-three".
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