Base | Representation |
---|---|
bin | 1011001101010011100000… |
… | …1010000001010101101111 |
3 | 1121122002100020011002012001 |
4 | 2303110320022001111233 |
5 | 3103400410022320442 |
6 | 42113111302553131 |
7 | 2411215315642525 |
oct | 263247012012557 |
9 | 47562306132161 |
10 | 12323203323247 |
11 | 3a21272013303 |
12 | 147039ba387a7 |
13 | 6b50c475945b |
14 | 308636618315 |
15 | 16584c6a32b7 |
hex | b353828156f |
12323203323247 has 2 divisors, whose sum is σ = 12323203323248. Its totient is φ = 12323203323246.
The previous prime is 12323203323199. The next prime is 12323203323281. The reversal of 12323203323247 is 74232330232321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12323203323247 is a prime.
It is a super-2 number, since 2×123232033232472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12323203323287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6161601661623 + 6161601661624.
It is an arithmetic number, because the mean of its divisors is an integer number (6161601661624).
Almost surely, 212323203323247 is an apocalyptic number.
12323203323247 is a deficient number, since it is larger than the sum of its proper divisors (1).
12323203323247 is an equidigital number, since it uses as much as digits as its factorization.
12323203323247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 217728, while the sum is 37.
Adding to 12323203323247 its reverse (74232330232321), we get a palindrome (86555533555568).
The spelling of 12323203323247 in words is "twelve trillion, three hundred twenty-three billion, two hundred three million, three hundred twenty-three thousand, two hundred forty-seven".
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